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CBSE CBSE English Medium Class 9. Solve the equation 23 x - 14 3x 12.
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6 x 2 3 x 2 x 1.
Since ab is negative a and b are both negative. Find the remainder when x3. Concept Notes Videos 289. First the expression needs to be rewritten as x 2 a x b x 2. Since ab is positive a and b have the same sign. 30119 Observe that 3x2-x-103x5x-2 x25x-14x7x-2 So we get lim_x to 23x2-x-10x25x-1lim_x to 23x5x7119.
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